Base | Representation |
---|---|
bin | 10110011000000100… |
… | …10110110000001101 |
3 | 1011000012202220212000 |
4 | 23030002112300031 |
5 | 144100323313031 |
6 | 5304014302513 |
7 | 603460462143 |
oct | 131402266015 |
9 | 34005686760 |
10 | 12013104141 |
11 | 51050a1a45 |
12 | 23b31b7a39 |
13 | 1195aa225c |
14 | 81d66d593 |
15 | 4a49ad3e6 |
hex | 2cc096c0d |
12013104141 has 32 divisors (see below), whose sum is σ = 18741888000. Its totient is φ = 7583983344.
The previous prime is 12013104127. The next prime is 12013104157. The reversal of 12013104141 is 14140131021.
12013104141 is a `hidden beast` number, since 120 + 131 + 0 + 414 + 1 = 666.
It is not a de Polignac number, because 12013104141 - 217 = 12012973069 is a prime.
It is a super-2 number, since 2×120131041412 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013104641) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1914976 + ... + 1921238.
It is an arithmetic number, because the mean of its divisors is an integer number (585684000).
Almost surely, 212013104141 is an apocalyptic number.
It is an amenable number.
12013104141 is a deficient number, since it is larger than the sum of its proper divisors (6728783859).
12013104141 is a wasteful number, since it uses less digits than its factorization.
12013104141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10030 (or 10024 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 12013104141 its reverse (14140131021), we get a palindrome (26153235162).
The spelling of 12013104141 in words is "twelve billion, thirteen million, one hundred four thousand, one hundred forty-one".
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