Search a number
-
+
120131103312 = 2432111937107881
BaseRepresentation
bin110111111100001011…
…1110010101001010000
3102111002010212100102200
41233320113302221100
53432012030301222
6131104254243200
711451650346543
oct1577027625120
9374063770380
10120131103312
1146a4696aa70
121b3477b6500
13b4363cb0ac
145b5891285a
1531d1750eac
hex1bf85f2a50

120131103312 has 240 divisors, whose sum is σ = 396505187520. Its totient is φ = 33554995200.

The previous prime is 120131103299. The next prime is 120131103319. The reversal of 120131103312 is 213301131021.

120131103312 is a `hidden beast` number, since 1 + 20 + 1 + 311 + 0 + 331 + 2 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120131103319) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1059612 + ... + 1167492.

It is an arithmetic number, because the mean of its divisors is an integer number (1652104948).

Almost surely, 2120131103312 is an apocalyptic number.

120131103312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120131103312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198252593760).

120131103312 is an abundant number, since it is smaller than the sum of its proper divisors (276374084208).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120131103312 is a wasteful number, since it uses less digits than its factorization.

120131103312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107962 (or 107953 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 120131103312 its reverse (213301131021), we get a palindrome (333432234333).

The spelling of 120131103312 in words is "one hundred twenty billion, one hundred thirty-one million, one hundred three thousand, three hundred twelve".