1201311103301 has 2 divisors, whose sum is σ = 1201311103302. Its totient is φ = 1201311103300.

The previous prime is 1201311103277. The next prime is 1201311103327. The reversal of 1201311103301 is 1033011131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1057801965025 + 143509138276 = 1028495^2 + 378826^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201311103301 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1201311103301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201311103331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600655551650 + 600655551651.

It is an arithmetic number, because the mean of its divisors is an integer number (600655551651).

Almost surely, 2^{1201311103301} is an apocalyptic number.

It is an amenable number.

1201311103301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201311103301 is an equidigital number, since it uses as much as digits as its factorization.

1201311103301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1201311103301 its reverse (1033011131021), we get a palindrome (2234322234322).

The spelling of 1201311103301 in words is "one trillion, two hundred one billion, three hundred eleven million, one hundred three thousand, three hundred one".