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1201311535201 is a prime number
BaseRepresentation
bin10001011110110011101…
…111110101000001100001
311020211210110121000001021
4101132303233311001201
5124140241223111301
62315512551205441
7152535422365561
oct21366357650141
94224713530037
101201311535201
11423523052988
121749a4976881
138938b23123b
14422027acda1
15213aee088a1
hex117b3bf5061

1201311535201 has 2 divisors, whose sum is σ = 1201311535202. Its totient is φ = 1201311535200.

The previous prime is 1201311535187. The next prime is 1201311535283. The reversal of 1201311535201 is 1025351131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 801383040000 + 399928495201 = 895200^2 + 632399^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201311535201 - 211 = 1201311533153 is a prime.

It is a super-2 number, since 2×12013115352012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201311535301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600655767600 + 600655767601.

It is an arithmetic number, because the mean of its divisors is an integer number (600655767601).

Almost surely, 21201311535201 is an apocalyptic number.

It is an amenable number.

1201311535201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201311535201 is an equidigital number, since it uses as much as digits as its factorization.

1201311535201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 1201311535201 its reverse (1025351131021), we get a palindrome (2226662666222).

The spelling of 1201311535201 in words is "one trillion, two hundred one billion, three hundred eleven million, five hundred thirty-five thousand, two hundred one".