Base | Representation |
---|---|
bin | 1010111011010000010111… |
… | …0000110001110110111000 |
3 | 1120112102222000001022211020 |
4 | 2232310011300301312320 |
5 | 3033310332232400440 |
6 | 41314430133302440 |
7 | 2346630213613554 |
oct | 256640560616670 |
9 | 46472860038736 |
10 | 12013120200120 |
11 | 39118101983a6 |
12 | 1420281794a20 |
13 | 691aa8958600 |
14 | 2d761c2b6864 |
15 | 15c74ebb73d0 |
hex | aed05c31db8 |
12013120200120 has 192 divisors, whose sum is σ = 39309731917920. Its totient is φ = 2935490568192.
The previous prime is 12013120200113. The next prime is 12013120200131. The reversal of 12013120200120 is 2100202131021.
12013120200120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 12013120200120.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 616452 + ... + 4940268.
Almost surely, 212013120200120 is an apocalyptic number.
12013120200120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12013120200120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19654865958960).
12013120200120 is an abundant number, since it is smaller than the sum of its proper divisors (27296611717800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013120200120 is a wasteful number, since it uses less digits than its factorization.
12013120200120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4323994 (or 4323977 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 12013120200120 its reverse (2100202131021), we get a palindrome (14113322331141).
The spelling of 12013120200120 in words is "twelve trillion, thirteen billion, one hundred twenty million, two hundred thousand, one hundred twenty".
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