Base | Representation |
---|---|
bin | 10001011110110011110… |
… | …010010111101001001011 |
3 | 11020211210111211211202021 |
4 | 101132303302113221023 |
5 | 124140241410420131 |
6 | 2315513013345311 |
7 | 152535431141536 |
oct | 21366362275113 |
9 | 4224714754667 |
10 | 1201312201291 |
11 | 423523468374 |
12 | 1749a5038237 |
13 | 8938b405487 |
14 | 42202903a1d |
15 | 213aeedae11 |
hex | 117b3c97a4b |
1201312201291 has 2 divisors, whose sum is σ = 1201312201292. Its totient is φ = 1201312201290.
The previous prime is 1201312201277. The next prime is 1201312201361. The reversal of 1201312201291 is 1921022131021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201312201291 - 215 = 1201312168523 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201312241291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600656100645 + 600656100646.
It is an arithmetic number, because the mean of its divisors is an integer number (600656100646).
Almost surely, 21201312201291 is an apocalyptic number.
1201312201291 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201312201291 is an equidigital number, since it uses as much as digits as its factorization.
1201312201291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 1201312201291 in words is "one trillion, two hundred one billion, three hundred twelve million, two hundred one thousand, two hundred ninety-one".
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