12013130000 has 200 divisors, whose sum is σ = 31958520000. Its totient is φ = 4352832000.

The previous prime is 12013129987. The next prime is 12013130009. The reversal of 12013130000 is 3131021.

It is a tau number, because it is divible by the number of its divisors (200).

It is not an unprimeable number, because it can be changed into a prime (12013130009) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 4368626 + ... + 4371374.

It is an arithmetic number, because the mean of its divisors is an integer number (159792600).

Almost surely, 2^12013130000 is an apocalyptic number.

12013130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12013130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15979260000).

12013130000 is an abundant number, since it is smaller than the sum of its proper divisors (19945390000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013130000 is a wasteful number, since it uses less digits than its factorization.

12013130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2819 (or 2798 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 12013130000 its reverse (3131021), we get a palindrome (12016261021).

The spelling of 12013130000 in words is "twelve billion, thirteen million, one hundred thirty thousand".