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12013130022 = 232002188337
BaseRepresentation
bin10110011000000100…
…11101000100100110
31011000012211020100120
423030002131010212
5144100330130042
65304015022410
7603460630455
oct131402350446
934005736316
1012013130022
11510510a433
1223b320aa06
131195ab0c7a
1481d678b9c
154a49b5dec
hex2cc09d126

12013130022 has 8 divisors (see below), whose sum is σ = 24026260056. Its totient is φ = 4004376672.

The previous prime is 12013130009. The next prime is 12013130089. The reversal of 12013130022 is 22003131021.

It is a sphenic number, since it is the product of 3 distinct primes.

12013130022 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 12013129983 and 12013130010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1001094163 + ... + 1001094174.

It is an arithmetic number, because the mean of its divisors is an integer number (3003282507).

Almost surely, 212013130022 is an apocalyptic number.

12013130022 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013130022 is a wasteful number, since it uses less digits than its factorization.

12013130022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2002188342.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12013130022 its reverse (22003131021), we get a palindrome (34016261043).

Subtracting 12013130022 from its reverse (22003131021), we obtain a palindrome (9990000999).

The spelling of 12013130022 in words is "twelve billion, thirteen million, one hundred thirty thousand, twenty-two".

Divisors: 1 2 3 6 2002188337 4004376674 6006565011 12013130022