Base | Representation |
---|---|
bin | 10110011000000100… |
… | …11101010011100101 |
3 | 1011000012211021200002 |
4 | 23030002131103211 |
5 | 144100330142411 |
6 | 5304015031045 |
7 | 603460633325 |
oct | 131402352345 |
9 | 34005737602 |
10 | 12013130981 |
11 | 5105110125 |
12 | 23b320b485 |
13 | 1195ab1537 |
14 | 81d679285 |
15 | 4a49b633b |
hex | 2cc09d4e5 |
12013130981 has 2 divisors, whose sum is σ = 12013130982. Its totient is φ = 12013130980.
The previous prime is 12013130947. The next prime is 12013131037. The reversal of 12013130981 is 18903131021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8955593956 + 3057537025 = 94634^2 + 55295^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013130981 - 226 = 11946022117 is a prime.
It is a super-2 number, since 2×120131309812 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013120981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006565490 + 6006565491.
It is an arithmetic number, because the mean of its divisors is an integer number (6006565491).
Almost surely, 212013130981 is an apocalyptic number.
It is an amenable number.
12013130981 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013130981 is an equidigital number, since it uses as much as digits as its factorization.
12013130981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 29.
The spelling of 12013130981 in words is "twelve billion, thirteen million, one hundred thirty thousand, nine hundred eighty-one".
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