12013131341 has 2 divisors, whose sum is σ = 12013131342. Its totient is φ = 12013131340.

The previous prime is 12013131337. The next prime is 12013131353. The reversal of 12013131341 is 14313131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11958297316 + 54834025 = 109354^2 + 7405^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013131341 - 2² = 12013131337 is a prime.

It is a super-2 number, since 2×12013131341² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013131301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006565670 + 6006565671.

It is an arithmetic number, because the mean of its divisors is an integer number (6006565671).

Almost surely, 2^12013131341 is an apocalyptic number.

It is an amenable number.

12013131341 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013131341 is an equidigital number, since it uses as much as digits as its factorization.

12013131341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 12013131341 its reverse (14313131021), we get a palindrome (26326262362).

The spelling of 12013131341 in words is "twelve billion, thirteen million, one hundred thirty-one thousand, three hundred forty-one".