Search a number
-
+
12013132333229 is a prime number
BaseRepresentation
bin1010111011010000011001…
…1111000100000010101101
31120112102222211212202022122
42232310012133010002231
53033310343334130404
641314431245322325
72346630422006216
oct256640637040255
946472884782278
1012013132333229
113911817025165
1214202858663a5
13691aab316071
142d761db5440d
1515c750cb23be
hexaed067c40ad

12013132333229 has 2 divisors, whose sum is σ = 12013132333230. Its totient is φ = 12013132333228.

The previous prime is 12013132333171. The next prime is 12013132333259. The reversal of 12013132333229 is 92233323131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9702458725129 + 2310673608100 = 3114877^2 + 1520090^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013132333229 - 28 = 12013132332973 is a prime.

It is a super-3 number, since 3×120131323332293 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013132333259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006566166614 + 6006566166615.

It is an arithmetic number, because the mean of its divisors is an integer number (6006566166615).

Almost surely, 212013132333229 is an apocalyptic number.

It is an amenable number.

12013132333229 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013132333229 is an equidigital number, since it uses as much as digits as its factorization.

12013132333229 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992, while the sum is 35.

The spelling of 12013132333229 in words is "twelve trillion, thirteen billion, one hundred thirty-two million, three hundred thirty-three thousand, two hundred twenty-nine".