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1201314001 is a prime number
BaseRepresentation
bin100011110011010…
…1001100011010001
310002201111002000011
41013212221203101
54430014022001
6315112154521
741525000116
oct10746514321
93081432004
101201314001
11567123a98
12296398a41
13161b645b4
14b579290d
15706e9d51
hex479a98d1

1201314001 has 2 divisors, whose sum is σ = 1201314002. Its totient is φ = 1201314000.

The previous prime is 1201313963. The next prime is 1201314011. The reversal of 1201314001 is 1004131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 971942976 + 229371025 = 31176^2 + 15145^2 .

It is an emirp because it is prime and its reverse (1004131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201314001 - 225 = 1167759569 is a prime.

It is not a weakly prime, because it can be changed into another prime (1201314011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600657000 + 600657001.

It is an arithmetic number, because the mean of its divisors is an integer number (600657001).

Almost surely, 21201314001 is an apocalyptic number.

It is an amenable number.

1201314001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201314001 is an equidigital number, since it uses as much as digits as its factorization.

1201314001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1201314001 is about 34659.9769330564. The cubic root of 1201314001 is about 1063.0462983687.

Adding to 1201314001 its reverse (1004131021), we get a palindrome (2205445022).

The spelling of 1201314001 in words is "one billion, two hundred one million, three hundred fourteen thousand, one".