12013144130893 has 2 divisors, whose sum is σ = 12013144130894. Its totient is φ = 12013144130892.

The previous prime is 12013144130861. The next prime is 12013144130903. The reversal of 12013144130893 is 39803144131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11847212552484 + 165931578409 = 3441978^2 + 407347^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013144130893 - 2⁵ = 12013144130861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013144130693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006572065446 + 6006572065447.

It is an arithmetic number, because the mean of its divisors is an integer number (6006572065447).

Almost surely, 2^{12013144130893} is an apocalyptic number.

It is an amenable number.

12013144130893 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013144130893 is an equidigital number, since it uses as much as digits as its factorization.

12013144130893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 40.

The spelling of 12013144130893 in words is "twelve trillion, thirteen billion, one hundred forty-four million, one hundred thirty thousand, eight hundred ninety-three".