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120132011313173 is a prime number
BaseRepresentation
bin11011010100001001101001…
…110111000100100000010101
3120202100111201102100120112202
4123110021221313010200111
5111221220324344010143
61103255514545254245
734206152141632256
oct3324115167044025
9522314642316482
10120132011313173
1135306777607732
121158247b634385
135205527c0a032
1421945c56dab2d
15dd4d98d63ab8
hex6d4269dc4815

120132011313173 has 2 divisors, whose sum is σ = 120132011313174. Its totient is φ = 120132011313172.

The previous prime is 120132011313163. The next prime is 120132011313227. The reversal of 120132011313173 is 371313110231021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 102766513813924 + 17365497499249 = 10137382^2 + 4167193^2 .

It is a cyclic number.

It is not a de Polignac number, because 120132011313173 - 210 = 120132011312149 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120132011313163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066005656586 + 60066005656587.

It is an arithmetic number, because the mean of its divisors is an integer number (60066005656587).

Almost surely, 2120132011313173 is an apocalyptic number.

It is an amenable number.

120132011313173 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132011313173 is an equidigital number, since it uses as much as digits as its factorization.

120132011313173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 29.

Adding to 120132011313173 its reverse (371313110231021), we get a palindrome (491445121544194).

The spelling of 120132011313173 in words is "one hundred twenty trillion, one hundred thirty-two billion, eleven million, three hundred thirteen thousand, one hundred seventy-three".