Base | Representation |
---|---|
bin | 11011010100001001101001… |
… | …110111000100100010000011 |
3 | 120202100111201102100120200211 |
4 | 123110021221313010202003 |
5 | 111221220324344011113 |
6 | 1103255514545254551 |
7 | 34206152141632504 |
oct | 3324115167044203 |
9 | 522314642316624 |
10 | 120132011313283 |
11 | 35306777607822 |
12 | 1158247b634457 |
13 | 5205527c0a0b8 |
14 | 21945c56dabab |
15 | dd4d98d63b3d |
hex | 6d4269dc4883 |
120132011313283 has 2 divisors, whose sum is σ = 120132011313284. Its totient is φ = 120132011313282.
The previous prime is 120132011313239. The next prime is 120132011313427. The reversal of 120132011313283 is 382313110231021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120132011313283 - 233 = 120123421378691 is a prime.
It is not a weakly prime, because it can be changed into another prime (120132011313883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066005656641 + 60066005656642.
It is an arithmetic number, because the mean of its divisors is an integer number (60066005656642).
Almost surely, 2120132011313283 is an apocalyptic number.
120132011313283 is a deficient number, since it is larger than the sum of its proper divisors (1).
120132011313283 is an equidigital number, since it uses as much as digits as its factorization.
120132011313283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 120132011313283 in words is "one hundred twenty trillion, one hundred thirty-two billion, eleven million, three hundred thirteen thousand, two hundred eighty-three".
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