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120132011313427 is a prime number
BaseRepresentation
bin11011010100001001101001…
…110111000100100100010011
3120202100111201102100120220011
4123110021221313010210103
5111221220324344012202
61103255514545255351
734206152141633101
oct3324115167044423
9522314642316804
10120132011313427
1135306777607943
121158247b634557
135205527c0a199
1421945c56dac71
15dd4d98d63bd7
hex6d4269dc4913

120132011313427 has 2 divisors, whose sum is σ = 120132011313428. Its totient is φ = 120132011313426.

The previous prime is 120132011313283. The next prime is 120132011313437. The reversal of 120132011313427 is 724313110231021.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120132011313427 - 219 = 120132010789139 is a prime.

It is not a weakly prime, because it can be changed into another prime (120132011313437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066005656713 + 60066005656714.

It is an arithmetic number, because the mean of its divisors is an integer number (60066005656714).

Almost surely, 2120132011313427 is an apocalyptic number.

120132011313427 is a deficient number, since it is larger than the sum of its proper divisors (1).

120132011313427 is an equidigital number, since it uses as much as digits as its factorization.

120132011313427 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 120132011313427 its reverse (724313110231021), we get a palindrome (844445121544448).

The spelling of 120132011313427 in words is "one hundred twenty trillion, one hundred thirty-two billion, eleven million, three hundred thirteen thousand, four hundred twenty-seven".