Base | Representation |
---|---|
bin | 11011010100001001101001… |
… | …110111000100100100010011 |
3 | 120202100111201102100120220011 |
4 | 123110021221313010210103 |
5 | 111221220324344012202 |
6 | 1103255514545255351 |
7 | 34206152141633101 |
oct | 3324115167044423 |
9 | 522314642316804 |
10 | 120132011313427 |
11 | 35306777607943 |
12 | 1158247b634557 |
13 | 5205527c0a199 |
14 | 21945c56dac71 |
15 | dd4d98d63bd7 |
hex | 6d4269dc4913 |
120132011313427 has 2 divisors, whose sum is σ = 120132011313428. Its totient is φ = 120132011313426.
The previous prime is 120132011313283. The next prime is 120132011313437. The reversal of 120132011313427 is 724313110231021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120132011313427 - 219 = 120132010789139 is a prime.
It is not a weakly prime, because it can be changed into another prime (120132011313437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066005656713 + 60066005656714.
It is an arithmetic number, because the mean of its divisors is an integer number (60066005656714).
Almost surely, 2120132011313427 is an apocalyptic number.
120132011313427 is a deficient number, since it is larger than the sum of its proper divisors (1).
120132011313427 is an equidigital number, since it uses as much as digits as its factorization.
120132011313427 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 120132011313427 its reverse (724313110231021), we get a palindrome (844445121544448).
The spelling of 120132011313427 in words is "one hundred twenty trillion, one hundred thirty-two billion, eleven million, three hundred thirteen thousand, four hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •