Base | Representation |
---|---|
bin | 11011010100001001101010… |
… | …011000101101010011010110 |
3 | 120202100111202000221120101001 |
4 | 123110021222120231103112 |
5 | 111221220334123143110 |
6 | 1103255515502253514 |
7 | 34206152306606305 |
oct | 3324115230552326 |
9 | 522314660846331 |
10 | 120132020131030 |
11 | 3530678158a716 |
12 | 1158248258729a |
13 | 52055299a67bb |
14 | 21945c695443c |
15 | dd4d99a0663a |
hex | 6d426a62d4d6 |
120132020131030 has 8 divisors (see below), whose sum is σ = 216237636235872. Its totient is φ = 48052808052408.
The previous prime is 120132020130931. The next prime is 120132020131031. The reversal of 120132020131030 is 30131020231021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 120132020130989 and 120132020131007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120132020131031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6006601006542 + ... + 6006601006561.
It is an arithmetic number, because the mean of its divisors is an integer number (27029704529484).
Almost surely, 2120132020131030 is an apocalyptic number.
120132020131030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120132020131030 is a deficient number, since it is larger than the sum of its proper divisors (96105616104842).
120132020131030 is a wasteful number, since it uses less digits than its factorization.
120132020131030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12013202013110.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 120132020131030 its reverse (30131020231021), we get a palindrome (150263040362051).
Subtracting from 120132020131030 its reverse (30131020231021), we obtain a palindrome (90000999900009).
The spelling of 120132020131030 in words is "one hundred twenty trillion, one hundred thirty-two billion, twenty million, one hundred thirty-one thousand, thirty".
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