Base | Representation |
---|---|
bin | 10110011000000101… |
… | …10011000101110101 |
3 | 1011000012222211001222 |
4 | 23030002303011311 |
5 | 144100341021323 |
6 | 5304021000125 |
7 | 603461454431 |
oct | 131402630565 |
9 | 34005884058 |
10 | 12013220213 |
11 | 5105171175 |
12 | 23b3253045 |
13 | 1195b13037 |
14 | 81d69d9c1 |
15 | 4a49d29c8 |
hex | 2cc0b3175 |
12013220213 has 2 divisors, whose sum is σ = 12013220214. Its totient is φ = 12013220212.
The previous prime is 12013220209. The next prime is 12013220251. The reversal of 12013220213 is 31202231021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10159228849 + 1853991364 = 100793^2 + 43058^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013220213 - 22 = 12013220209 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12013220191 and 12013220200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12015220213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006610106 + 6006610107.
It is an arithmetic number, because the mean of its divisors is an integer number (6006610107).
Almost surely, 212013220213 is an apocalyptic number.
It is an amenable number.
12013220213 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013220213 is an equidigital number, since it uses as much as digits as its factorization.
12013220213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 12013220213 its reverse (31202231021), we get a palindrome (43215451234).
The spelling of 12013220213 in words is "twelve billion, thirteen million, two hundred twenty thousand, two hundred thirteen".
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