Search a number
-
+
12013233002101 = 15179557834451
BaseRepresentation
bin1010111011010000110001…
…1111000101011001110101
31120112110020212022021001101
42232310030133011121311
53033311100122031401
641314445243130101
72346633053455402
oct256641437053165
946473225267041
1012013233002101
113911868933181
1214202b3513931
13691ac6132146
142d762d27b2a9
1515c759a4a101
hexaed0c7c5675

12013233002101 has 4 divisors (see below), whose sum is σ = 12092790836704. Its totient is φ = 11933675167500.

The previous prime is 12013233002081. The next prime is 12013233002123. The reversal of 12013233002101 is 10120033231021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013233002101 - 215 = 12013232969333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013233002171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39778917075 + ... + 39778917376.

It is an arithmetic number, because the mean of its divisors is an integer number (3023197709176).

Almost surely, 212013233002101 is an apocalyptic number.

It is an amenable number.

12013233002101 is a deficient number, since it is larger than the sum of its proper divisors (79557834603).

12013233002101 is an equidigital number, since it uses as much as digits as its factorization.

12013233002101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79557834602.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12013233002101 its reverse (10120033231021), we get a palindrome (22133266233122).

The spelling of 12013233002101 in words is "twelve trillion, thirteen billion, two hundred thirty-three million, two thousand, one hundred one".

Divisors: 1 151 79557834451 12013233002101