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12013232969333 is a prime number
BaseRepresentation
bin1010111011010000110001…
…1110111101011001110101
31120112110020212020121002202
42232310030132331121311
53033311100120004313
641314445242314245
72346633053261021
oct256641436753165
946473225217082
1012013232969333
1139118689105a2
1214202b34b8985
13691ac612025b
142d762d26d381
1515c759a40558
hexaed0c7bd675

12013232969333 has 2 divisors, whose sum is σ = 12013232969334. Its totient is φ = 12013232969332.

The previous prime is 12013232969279. The next prime is 12013232969359. The reversal of 12013232969333 is 33396923231021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9729770470564 + 2283462498769 = 3119258^2 + 1511113^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013232969333 - 238 = 11738355062389 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013232969033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006616484666 + 6006616484667.

It is an arithmetic number, because the mean of its divisors is an integer number (6006616484667).

Almost surely, 212013232969333 is an apocalyptic number.

It is an amenable number.

12013232969333 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013232969333 is an equidigital number, since it uses as much as digits as its factorization.

12013232969333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 944784, while the sum is 47.

The spelling of 12013232969333 in words is "twelve trillion, thirteen billion, two hundred thirty-two million, nine hundred sixty-nine thousand, three hundred thirty-three".