Base | Representation |
---|---|
bin | 10001011110110100100… |
… | …000001011100011100001 |
3 | 11020211211100102222011010 |
4 | 101132310200023203201 |
5 | 124140302444213101 |
6 | 2315514123011133 |
7 | 152535635206530 |
oct | 21366440134341 |
9 | 4224740388133 |
10 | 1201324210401 |
11 | 42352a21aa57 |
12 | 1749a9069aa9 |
13 | 89390a4b663 |
14 | 4220434c317 |
15 | 213b10ae2d6 |
hex | 117b480b8e1 |
1201324210401 has 32 divisors (see below), whose sum is σ = 1877295771648. Its totient is φ = 669077256960.
The previous prime is 1201324210397. The next prime is 1201324210403. The reversal of 1201324210401 is 1040124231021.
It is not a de Polignac number, because 1201324210401 - 22 = 1201324210397 is a prime.
It is a super-3 number, since 3×12013242104013 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1201324210403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2287335 + ... + 2763068.
It is an arithmetic number, because the mean of its divisors is an integer number (58665492864).
Almost surely, 21201324210401 is an apocalyptic number.
It is an amenable number.
1201324210401 is a deficient number, since it is larger than the sum of its proper divisors (675971561247).
1201324210401 is a wasteful number, since it uses less digits than its factorization.
1201324210401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5050701.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 1201324210401 its reverse (1040124231021), we get a palindrome (2241448441422).
The spelling of 1201324210401 in words is "one trillion, two hundred one billion, three hundred twenty-four million, two hundred ten thousand, four hundred one".
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