1201325112431 has 2 divisors, whose sum is σ = 1201325112432. Its totient is φ = 1201325112430.

The previous prime is 1201325112413. The next prime is 1201325112451. The reversal of 1201325112431 is 1342115231021.

Together with previous prime (1201325112413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1201325112431 - 2¹⁴ = 1201325096047 is a prime.

It is a super-2 number, since 2×1201325112431² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1201325112431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201325112451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600662556215 + 600662556216.

It is an arithmetic number, because the mean of its divisors is an integer number (600662556216).

Almost surely, 2^{1201325112431} is an apocalyptic number.

1201325112431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201325112431 is an equidigital number, since it uses as much as digits as its factorization.

1201325112431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

The spelling of 1201325112431 in words is "one trillion, two hundred one billion, three hundred twenty-five million, one hundred twelve thousand, four hundred thirty-one".