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1201330111 is a prime number
BaseRepresentation
bin100011110011010…
…1101011110111111
310002201111220002211
41013212231132333
54430020030421
6315112401251
741525065102
oct10746553677
93081456084
101201330111
11567135103
122963a6227
13161b6ba27
14b5798739
15706ee9e1
hex479ad7bf

1201330111 has 2 divisors, whose sum is σ = 1201330112. Its totient is φ = 1201330110.

The previous prime is 1201330103. The next prime is 1201330147. The reversal of 1201330111 is 1110331021.

It is a weak prime.

It is an emirp because it is prime and its reverse (1110331021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201330111 - 23 = 1201330103 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201330091 and 1201330100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201334111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600665055 + 600665056.

It is an arithmetic number, because the mean of its divisors is an integer number (600665056).

Almost surely, 21201330111 is an apocalyptic number.

1201330111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201330111 is an equidigital number, since it uses as much as digits as its factorization.

1201330111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1201330111 is about 34660.2093328935. The cubic root of 1201330111 is about 1063.0510502763.

Adding to 1201330111 its reverse (1110331021), we get a palindrome (2311661132).

It can be divided in two parts, 12013 and 30111, that added together give a palindrome (42124).

The spelling of 1201330111 in words is "one billion, two hundred one million, three hundred thirty thousand, one hundred eleven".