Base | Representation |
---|---|
bin | 10001011110110100111… |
… | …011001110101101100111 |
3 | 11020211211211210012221011 |
4 | 101132310323032231213 |
5 | 124140311303114343 |
6 | 2315514535003051 |
7 | 152536052401504 |
oct | 21366473165547 |
9 | 4224754705834 |
10 | 1201331301223 |
11 | 423533223439 |
12 | 1749ab509487 |
13 | 89392362001 |
14 | 422052764ab |
15 | 213b1a1029d |
hex | 117b4eceb67 |
1201331301223 has 2 divisors, whose sum is σ = 1201331301224. Its totient is φ = 1201331301222.
The previous prime is 1201331301167. The next prime is 1201331301241. The reversal of 1201331301223 is 3221031331021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201331301223 - 213 = 1201331293031 is a prime.
It is a super-2 number, since 2×12013313012232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1201331301194 and 1201331301203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201331301253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600665650611 + 600665650612.
It is an arithmetic number, because the mean of its divisors is an integer number (600665650612).
Almost surely, 21201331301223 is an apocalyptic number.
1201331301223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201331301223 is an equidigital number, since it uses as much as digits as its factorization.
1201331301223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1201331301223 its reverse (3221031331021), we get a palindrome (4422362632244).
The spelling of 1201331301223 in words is "one trillion, two hundred one billion, three hundred thirty-one million, three hundred one thousand, two hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •