Base | Representation |
---|---|
bin | 1110010100100… |
… | …01011001011100 |
3 | 22101001101210020 |
4 | 13022101121130 |
5 | 221223230322 |
6 | 15530512140 |
7 | 2656054413 |
oct | 712213134 |
9 | 271041706 |
10 | 120133212 |
11 | 618a2951 |
12 | 34295650 |
13 | 1bb72754 |
14 | 11d5247a |
15 | a83005c |
hex | 729165c |
120133212 has 12 divisors (see below), whose sum is σ = 280310856. Its totient is φ = 40044400.
The previous prime is 120133193. The next prime is 120133231. The reversal of 120133212 is 212331021.
It is an interprime number because it is at equal distance from previous prime (120133193) and next prime (120133231).
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 120133191 and 120133200.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5005539 + ... + 5005562.
It is an arithmetic number, because the mean of its divisors is an integer number (23359238).
Almost surely, 2120133212 is an apocalyptic number.
120133212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
120133212 is an abundant number, since it is smaller than the sum of its proper divisors (160177644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120133212 is a wasteful number, since it uses less digits than its factorization.
120133212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10011108 (or 10011106 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
The square root of 120133212 is about 10960.5297317237. The cubic root of 120133212 is about 493.4248635056.
Adding to 120133212 its reverse (212331021), we get a palindrome (332464233).
It can be divided in two parts, 12013 and 3212, that added together give a triangular number (15225 = T174).
The spelling of 120133212 in words is "one hundred twenty million, one hundred thirty-three thousand, two hundred twelve".
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