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120133311310 = 2512013331131
BaseRepresentation
bin110111111100010000…
…0001101101101001110
3102111002022000112020101
41233320200031231032
53432013111430220
6131104413441314
711452005204055
oct1577040155516
9374068015211
10120133311310
1146a48138961
121b3484a023a
13b4369c20bc
145b58d2939c
1531d1a3a30a
hex1bf880db4e

120133311310 has 8 divisors (see below), whose sum is σ = 216239960376. Its totient is φ = 48053324520.

The previous prime is 120133311271. The next prime is 120133311329. The reversal of 120133311310 is 13113331021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1201333113102 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6006665556 + ... + 6006665575.

It is an arithmetic number, because the mean of its divisors is an integer number (27029995047).

Almost surely, 2120133311310 is an apocalyptic number.

120133311310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

120133311310 is a deficient number, since it is larger than the sum of its proper divisors (96106649066).

120133311310 is a wasteful number, since it uses less digits than its factorization.

120133311310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12013331138.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 120133311310 its reverse (13113331021), we get a palindrome (133246642331).

The spelling of 120133311310 in words is "one hundred twenty billion, one hundred thirty-three million, three hundred eleven thousand, three hundred ten".

Divisors: 1 2 5 10 12013331131 24026662262 60066655655 120133311310