120133313020120 has 16 divisors (see below), whose sum is σ = 270299954295360. Its totient is φ = 48053325208032.

The previous prime is 120133313020093. The next prime is 120133313020157. The reversal of 120133313020120 is 21020313331021.

It is a junction number, because it is equal to n+sod(n) for n = 120133313020091 and 120133313020100.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1501666412712 + ... + 1501666412791.

It is an arithmetic number, because the mean of its divisors is an integer number (16893747143460).

Almost surely, 2^{120133313020120} is an apocalyptic number.

120133313020120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

120133313020120 is an abundant number, since it is smaller than the sum of its proper divisors (150166641275240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120133313020120 is a wasteful number, since it uses less digits than its factorization.

120133313020120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3003332825514 (or 3003332825510 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 120133313020120 its reverse (21020313331021), we get a palindrome (141153626351141).

The spelling of 120133313020120 in words is "one hundred twenty trillion, one hundred thirty-three billion, three hundred thirteen million, twenty thousand, one hundred twenty".