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120133321086949 is a prime number
BaseRepresentation
bin11011010100001010110111…
…111011011101011111100101
3120202100122002200220222101121
4123110022313323131133211
5111221231020144240244
61103300252534253541
734206226454550562
oct3324126773353745
9522318080828347
10120133321086949
11353072899800a5
12115827861b72b1
1352056a63878c1
1421946ab643869
15dd4e23d34c84
hex6d42b7edd7e5

120133321086949 has 2 divisors, whose sum is σ = 120133321086950. Its totient is φ = 120133321086948.

The previous prime is 120133321086907. The next prime is 120133321086971. The reversal of 120133321086949 is 949680123331021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65496535698049 + 54636785388900 = 8092993^2 + 7391670^2 .

It is a cyclic number.

It is not a de Polignac number, because 120133321086949 - 221 = 120133318989797 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120133321086896 and 120133321086905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120133321686949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066660543474 + 60066660543475.

It is an arithmetic number, because the mean of its divisors is an integer number (60066660543475).

Almost surely, 2120133321086949 is an apocalyptic number.

It is an amenable number.

120133321086949 is a deficient number, since it is larger than the sum of its proper divisors (1).

120133321086949 is an equidigital number, since it uses as much as digits as its factorization.

120133321086949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 52.

The spelling of 120133321086949 in words is "one hundred twenty trillion, one hundred thirty-three billion, three hundred twenty-one million, eighty-six thousand, nine hundred forty-nine".