Base | Representation |
---|---|
bin | 11011010100001010110111… |
… | …111011100001011111111001 |
3 | 120202100122002200221210220011 |
4 | 123110022313323201133321 |
5 | 111221231020200301403 |
6 | 1103300252534501521 |
7 | 34206226454646445 |
oct | 3324126773413771 |
9 | 522318080853804 |
10 | 120133321103353 |
11 | 35307289991458 |
12 | 115827862048a1 |
13 | 52056a63921cc |
14 | 21946ab649825 |
15 | dd4e23d39a6d |
hex | 6d42b7ee17f9 |
120133321103353 has 2 divisors, whose sum is σ = 120133321103354. Its totient is φ = 120133321103352.
The previous prime is 120133321103347. The next prime is 120133321103413. The reversal of 120133321103353 is 353301123331021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60432401773584 + 59700919329769 = 7773828^2 + 7726637^2 .
It is an emirp because it is prime and its reverse (353301123331021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 120133321103353 - 237 = 119995882149881 is a prime.
It is a super-2 number, since 2×1201333211033532 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120133321103333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066660551676 + 60066660551677.
It is an arithmetic number, because the mean of its divisors is an integer number (60066660551677).
Almost surely, 2120133321103353 is an apocalyptic number.
It is an amenable number.
120133321103353 is a deficient number, since it is larger than the sum of its proper divisors (1).
120133321103353 is an equidigital number, since it uses as much as digits as its factorization.
120133321103353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 31.
Adding to 120133321103353 its reverse (353301123331021), we get a palindrome (473434444434374).
The spelling of 120133321103353 in words is "one hundred twenty trillion, one hundred thirty-three billion, three hundred twenty-one million, one hundred three thousand, three hundred fifty-three".
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