12013333101331 has 2 divisors, whose sum is σ = 12013333101332. Its totient is φ = 12013333101330.

The previous prime is 12013333101307. The next prime is 12013333101349. The reversal of 12013333101331 is 13310133331021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12013333101331 - 2⁵ = 12013333101299 is a prime.

It is a super-2 number, since 2×12013333101331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013333101296 and 12013333101305.

It is not a weakly prime, because it can be changed into another prime (12013333101361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006666550665 + 6006666550666.

It is an arithmetic number, because the mean of its divisors is an integer number (6006666550666).

Almost surely, 2^{12013333101331} is an apocalyptic number.

12013333101331 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013333101331 is an equidigital number, since it uses as much as digits as its factorization.

12013333101331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 12013333101331 its reverse (13310133331021), we get a palindrome (25323466432352).

The spelling of 12013333101331 in words is "twelve trillion, thirteen billion, three hundred thirty-three million, one hundred one thousand, three hundred thirty-one".