Base | Representation |
---|---|
bin | 1010111011010001001110… |
… | …1101001011001111010100 |
3 | 1120112110120022020112020210 |
4 | 2232310103231023033110 |
5 | 3033311322124332112 |
6 | 41314505251325420 |
7 | 2346636054213120 |
oct | 256642355131724 |
9 | 46473508215223 |
10 | 12013354136532 |
11 | 391192024a281 |
12 | 1420327bb0870 |
13 | 691b15265518 |
14 | 2d76413b0580 |
15 | 15c7654c6b3c |
hex | aed13b4b3d4 |
12013354136532 has 24 divisors (see below), whose sum is σ = 32035611030976. Its totient is φ = 3432386896128.
The previous prime is 12013354136519. The next prime is 12013354136543. The reversal of 12013354136532 is 23563145331021.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71508060253 + ... + 71508060420.
Almost surely, 212013354136532 is an apocalyptic number.
12013354136532 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12013354136532 is an abundant number, since it is smaller than the sum of its proper divisors (20022256894444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013354136532 is a wasteful number, since it uses less digits than its factorization.
12013354136532 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143016120687 (or 143016120685 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 39.
Adding to 12013354136532 its reverse (23563145331021), we get a palindrome (35576499467553).
The spelling of 12013354136532 in words is "twelve trillion, thirteen billion, three hundred fifty-four million, one hundred thirty-six thousand, five hundred thirty-two".
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