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12013354136532 = 2237143016120673
BaseRepresentation
bin1010111011010001001110…
…1101001011001111010100
31120112110120022020112020210
42232310103231023033110
53033311322124332112
641314505251325420
72346636054213120
oct256642355131724
946473508215223
1012013354136532
11391192024a281
121420327bb0870
13691b15265518
142d76413b0580
1515c7654c6b3c
hexaed13b4b3d4

12013354136532 has 24 divisors (see below), whose sum is σ = 32035611030976. Its totient is φ = 3432386896128.

The previous prime is 12013354136519. The next prime is 12013354136543. The reversal of 12013354136532 is 23563145331021.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71508060253 + ... + 71508060420.

Almost surely, 212013354136532 is an apocalyptic number.

12013354136532 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12013354136532 is an abundant number, since it is smaller than the sum of its proper divisors (20022256894444).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013354136532 is a wasteful number, since it uses less digits than its factorization.

12013354136532 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 143016120687 (or 143016120685 counting only the distinct ones).

The product of its (nonzero) digits is 194400, while the sum is 39.

Adding to 12013354136532 its reverse (23563145331021), we get a palindrome (35576499467553).

The spelling of 12013354136532 in words is "twelve trillion, thirteen billion, three hundred fifty-four million, one hundred thirty-six thousand, five hundred thirty-two".

Divisors: 1 2 3 4 6 7 12 14 21 28 42 84 143016120673 286032241346 429048362019 572064482692 858096724038 1001112844711 1716193448076 2002225689422 3003338534133 4004451378844 6006677068266 12013354136532