1201340341207 has 2 divisors, whose sum is σ = 1201340341208. Its totient is φ = 1201340341206.

The previous prime is 1201340341121. The next prime is 1201340341291. The reversal of 1201340341207 is 7021430431021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1201340341207 - 2¹¹ = 1201340339159 is a prime.

It is a super-2 number, since 2×1201340341207² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201340341297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600670170603 + 600670170604.

It is an arithmetic number, because the mean of its divisors is an integer number (600670170604).

Almost surely, 2^{1201340341207} is an apocalyptic number.

1201340341207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201340341207 is an equidigital number, since it uses as much as digits as its factorization.

1201340341207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 28.

Adding to 1201340341207 its reverse (7021430431021), we get a palindrome (8222770772228).

The spelling of 1201340341207 in words is "one trillion, two hundred one billion, three hundred forty million, three hundred forty-one thousand, two hundred seven".