Base | Representation |
---|---|
bin | 100011110011011… |
… | …0000011011000011 |
3 | 10002201112111121121 |
4 | 1013212300123003 |
5 | 4430020422042 |
6 | 315112533111 |
7 | 41525145145 |
oct | 10746603303 |
9 | 3081474547 |
10 | 1201342147 |
11 | 567143155 |
12 | 2963b1197 |
13 | 161b74355 |
14 | b579cc95 |
15 | 70703367 |
hex | 479b06c3 |
1201342147 has 2 divisors, whose sum is σ = 1201342148. Its totient is φ = 1201342146.
The previous prime is 1201342097. The next prime is 1201342157. The reversal of 1201342147 is 7412431021.
It is a strong prime.
It is an emirp because it is prime and its reverse (7412431021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201342147 - 211 = 1201340099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201342157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600671073 + 600671074.
It is an arithmetic number, because the mean of its divisors is an integer number (600671074).
Almost surely, 21201342147 is an apocalyptic number.
1201342147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201342147 is an equidigital number, since it uses as much as digits as its factorization.
1201342147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
The square root of 1201342147 is about 34660.3829609541. The cubic root of 1201342147 is about 1063.0546004633.
Adding to 1201342147 its reverse (7412431021), we get a palindrome (8613773168).
The spelling of 1201342147 in words is "one billion, two hundred one million, three hundred forty-two thousand, one hundred forty-seven".
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