Base | Representation |
---|---|
bin | 10110011000000111… |
… | …00111011001010001 |
3 | 1011000020101200221122 |
4 | 23030003213121101 |
5 | 144100414400244 |
6 | 5304025332025 |
7 | 603463336142 |
oct | 131403473121 |
9 | 34006350848 |
10 | 12013434449 |
11 | 51052a8125 |
12 | 23b3337015 |
13 | 1195b896c3 |
14 | 81d717ac9 |
15 | 4a4a261ee |
hex | 2cc0e7651 |
12013434449 has 2 divisors, whose sum is σ = 12013434450. Its totient is φ = 12013434448.
The previous prime is 12013434431. The next prime is 12013434463. The reversal of 12013434449 is 94443431021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6763417600 + 5250016849 = 82240^2 + 72457^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12013434449 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013434409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006717224 + 6006717225.
It is an arithmetic number, because the mean of its divisors is an integer number (6006717225).
Almost surely, 212013434449 is an apocalyptic number.
It is an amenable number.
12013434449 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013434449 is an equidigital number, since it uses as much as digits as its factorization.
12013434449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
The spelling of 12013434449 in words is "twelve billion, thirteen million, four hundred thirty-four thousand, four hundred forty-nine".
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