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12013434431 is a prime number
BaseRepresentation
bin10110011000000111…
…00111011000111111
31011000020101200220222
423030003213120333
5144100414400211
65304025331555
7603463336115
oct131403473077
934006350828
1012013434431
1151052a8109
1223b3336bbb
131195b896ab
1481d717ab5
154a4a261db
hex2cc0e763f

12013434431 has 2 divisors, whose sum is σ = 12013434432. Its totient is φ = 12013434430.

The previous prime is 12013434409. The next prime is 12013434449. The reversal of 12013434431 is 13443431021.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12013434431 - 214 = 12013418047 is a prime.

It is a super-2 number, since 2×120134344312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12013434431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013434491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006717215 + 6006717216.

It is an arithmetic number, because the mean of its divisors is an integer number (6006717216).

Almost surely, 212013434431 is an apocalyptic number.

12013434431 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013434431 is an equidigital number, since it uses as much as digits as its factorization.

12013434431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 12013434431 its reverse (13443431021), we get a palindrome (25456865452).

The spelling of 12013434431 in words is "twelve billion, thirteen million, four hundred thirty-four thousand, four hundred thirty-one".