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1201344013 is a prime number
BaseRepresentation
bin100011110011011…
…0000111000001101
310002201112121011201
41013212300320031
54430021002023
6315112545501
741525153452
oct10746607015
93081477151
101201344013
115671445a1
122963b2291
13161b7515c
14b579d829
1570703bad
hex479b0e0d

1201344013 has 2 divisors, whose sum is σ = 1201344014. Its totient is φ = 1201344012.

The previous prime is 1201344007. The next prime is 1201344029. The reversal of 1201344013 is 3104431021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1075971204 + 125372809 = 32802^2 + 11197^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1201344013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201344043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600672006 + 600672007.

It is an arithmetic number, because the mean of its divisors is an integer number (600672007).

Almost surely, 21201344013 is an apocalyptic number.

It is an amenable number.

1201344013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201344013 is an equidigital number, since it uses as much as digits as its factorization.

1201344013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 1201344013 is about 34660.4098792845. The cubic root of 1201344013 is about 1063.0551508641.

Adding to 1201344013 its reverse (3104431021), we get a palindrome (4305775034).

The spelling of 1201344013 in words is "one billion, two hundred one million, three hundred forty-four thousand, thirteen".