Base | Representation |
---|---|
bin | 11011010100001011111010… |
… | …001001110000101110111011 |
3 | 120202100201222010112220201022 |
4 | 123110023322021300232323 |
5 | 111221240304111211102 |
6 | 1103300555104013055 |
7 | 34206266135355215 |
oct | 3324137211605673 |
9 | 522321863486638 |
10 | 120134432132027 |
11 | 353077aa049775 |
12 | 11582a3630118b |
13 | 5205822604a21 |
14 | 21947750195b5 |
15 | dd4e8b64d5a2 |
hex | 6d42fa270bbb |
120134432132027 has 2 divisors, whose sum is σ = 120134432132028. Its totient is φ = 120134432132026.
The previous prime is 120134432131979. The next prime is 120134432132041. The reversal of 120134432132027 is 720231234431021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120134432132027 - 26 = 120134432131963 is a prime.
It is not a weakly prime, because it can be changed into another prime (120134432182027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60067216066013 + 60067216066014.
It is an arithmetic number, because the mean of its divisors is an integer number (60067216066014).
Almost surely, 2120134432132027 is an apocalyptic number.
120134432132027 is a deficient number, since it is larger than the sum of its proper divisors (1).
120134432132027 is an equidigital number, since it uses as much as digits as its factorization.
120134432132027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384, while the sum is 35.
Adding to 120134432132027 its reverse (720231234431021), we get a palindrome (840365666563048).
The spelling of 120134432132027 in words is "one hundred twenty trillion, one hundred thirty-four billion, four hundred thirty-two million, one hundred thirty-two thousand, twenty-seven".
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