120134432132041 has 2 divisors, whose sum is σ = 120134432132042. Its totient is φ = 120134432132040.

The previous prime is 120134432132027. The next prime is 120134432132129. The reversal of 120134432132041 is 140231234431021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113155874375625 + 6978557756416 = 10637475^2 + 2641696^2 .

It is an emirp because it is prime and its reverse (140231234431021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120134432132041 - 2⁴¹ = 117935408876489 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120134432131994 and 120134432132012.

It is not a weakly prime, because it can be changed into another prime (120134432132941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60067216066020 + 60067216066021.

It is an arithmetic number, because the mean of its divisors is an integer number (60067216066021).

Almost surely, 2^{120134432132041} is an apocalyptic number.

It is an amenable number.

120134432132041 is a deficient number, since it is larger than the sum of its proper divisors (1).

120134432132041 is an equidigital number, since it uses as much as digits as its factorization.

120134432132041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 120134432132041 its reverse (140231234431021), we get a palindrome (260365666563062).

The spelling of 120134432132041 in words is "one hundred twenty trillion, one hundred thirty-four billion, four hundred thirty-two million, one hundred thirty-two thousand, forty-one".