Base | Representation |
---|---|
bin | 11011010100001011111010… |
… | …001001110000111001100111 |
3 | 120202100201222010112221122122 |
4 | 123110023322021300321213 |
5 | 111221240304111221321 |
6 | 1103300555104020155 |
7 | 34206266135360213 |
oct | 3324137211607147 |
9 | 522321863487578 |
10 | 120134432132711 |
11 | 353077aa04a237 |
12 | 11582a3630165b |
13 | 5205822605129 |
14 | 2194775019943 |
15 | dd4e8b64d8ab |
hex | 6d42fa270e67 |
120134432132711 has 2 divisors, whose sum is σ = 120134432132712. Its totient is φ = 120134432132710.
The previous prime is 120134432132639. The next prime is 120134432132789. The reversal of 120134432132711 is 117231234431021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120134432132711 - 230 = 120133358390887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120134432132791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60067216066355 + 60067216066356.
It is an arithmetic number, because the mean of its divisors is an integer number (60067216066356).
Almost surely, 2120134432132711 is an apocalyptic number.
120134432132711 is a deficient number, since it is larger than the sum of its proper divisors (1).
120134432132711 is an equidigital number, since it uses as much as digits as its factorization.
120134432132711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
Adding to 120134432132711 its reverse (117231234431021), we get a palindrome (237365666563732).
The spelling of 120134432132711 in words is "one hundred twenty trillion, one hundred thirty-four billion, four hundred thirty-two million, one hundred thirty-two thousand, seven hundred eleven".
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