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1201356402397 is a prime number
BaseRepresentation
bin10001011110110110011…
…010111110111011011101
311020211220121000111021021
4101132312122332323131
5124140334214334042
62315521233004141
7152536505634664
oct21366632767335
94224817014237
101201356402397
11423546408308
121749b79b3651
1389397610288
144220872bddb
15213b3d1c867
hex117b66beedd

1201356402397 has 2 divisors, whose sum is σ = 1201356402398. Its totient is φ = 1201356402396.

The previous prime is 1201356402377. The next prime is 1201356402401. The reversal of 1201356402397 is 7932046531021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1138619177721 + 62737224676 = 1067061^2 + 250474^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1201356402397 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201356402377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600678201198 + 600678201199.

It is an arithmetic number, because the mean of its divisors is an integer number (600678201199).

Almost surely, 21201356402397 is an apocalyptic number.

It is an amenable number.

1201356402397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201356402397 is an equidigital number, since it uses as much as digits as its factorization.

1201356402397 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 272160, while the sum is 43.

The spelling of 1201356402397 in words is "one trillion, two hundred one billion, three hundred fifty-six million, four hundred two thousand, three hundred ninety-seven".