Base | Representation |
---|---|
bin | 1010111011010011100101… |
… | …1000011100100010001101 |
3 | 1120112112012100122112110211 |
4 | 2232310321120130202031 |
5 | 3033314120434032212 |
6 | 41315052111402421 |
7 | 2346660531035254 |
oct | 256647130344215 |
9 | 46475170575424 |
10 | 12013986236557 |
11 | 3912115032398 |
12 | 1420483823411 |
13 | 691bb61bcbc6 |
14 | 2d76a131179b |
15 | 15c7a0c359a7 |
hex | aed3961c88d |
12013986236557 has 2 divisors, whose sum is σ = 12013986236558. Its totient is φ = 12013986236556.
The previous prime is 12013986236531. The next prime is 12013986236561. The reversal of 12013986236557 is 75563268931021.
12013986236557 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11564005546921 + 449980689636 = 3400589^2 + 670806^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013986236557 - 219 = 12013985712269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013986236587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006993118278 + 6006993118279.
It is an arithmetic number, because the mean of its divisors is an integer number (6006993118279).
Almost surely, 212013986236557 is an apocalyptic number.
It is an amenable number.
12013986236557 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013986236557 is an equidigital number, since it uses as much as digits as its factorization.
12013986236557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16329600, while the sum is 58.
The spelling of 12013986236557 in words is "twelve trillion, thirteen billion, nine hundred eighty-six million, two hundred thirty-six thousand, five hundred fifty-seven".
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