Search a number
-
+
12013986236557 is a prime number
BaseRepresentation
bin1010111011010011100101…
…1000011100100010001101
31120112112012100122112110211
42232310321120130202031
53033314120434032212
641315052111402421
72346660531035254
oct256647130344215
946475170575424
1012013986236557
113912115032398
121420483823411
13691bb61bcbc6
142d76a131179b
1515c7a0c359a7
hexaed3961c88d

12013986236557 has 2 divisors, whose sum is σ = 12013986236558. Its totient is φ = 12013986236556.

The previous prime is 12013986236531. The next prime is 12013986236561. The reversal of 12013986236557 is 75563268931021.

12013986236557 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11564005546921 + 449980689636 = 3400589^2 + 670806^2 .

It is a cyclic number.

It is not a de Polignac number, because 12013986236557 - 219 = 12013985712269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12013986236587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006993118278 + 6006993118279.

It is an arithmetic number, because the mean of its divisors is an integer number (6006993118279).

Almost surely, 212013986236557 is an apocalyptic number.

It is an amenable number.

12013986236557 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013986236557 is an equidigital number, since it uses as much as digits as its factorization.

12013986236557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16329600, while the sum is 58.

The spelling of 12013986236557 in words is "twelve trillion, thirteen billion, nine hundred eighty-six million, two hundred thirty-six thousand, five hundred fifty-seven".