12014012021 has 8 divisors (see below), whose sum is σ = 13111797888. Its totient is φ = 10917160000.

The previous prime is 12014011993. The next prime is 12014012029. The reversal of 12014012021 is 12021041021.

It is a happy number.

12014012021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12014012021 is a prime.

It is a super-3 number, since 3×12014012021³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12014011987 and 12014012005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12014012029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 206420 + ... + 258141.

It is an arithmetic number, because the mean of its divisors is an integer number (1638974736).

Almost surely, 2^12014012021 is an apocalyptic number.

12014012021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12014012021 is a deficient number, since it is larger than the sum of its proper divisors (1097785867).

12014012021 is a wasteful number, since it uses less digits than its factorization.

12014012021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 466923.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 12014012021 its reverse (12021041021), we get a palindrome (24035053042).

The spelling of 12014012021 in words is "twelve billion, fourteen million, twelve thousand, twenty-one".