Base | Representation |
---|---|
bin | 10001011110111001001… |
… | …010000111110100111011 |
3 | 11020212000210102001012121 |
4 | 101132321022013310323 |
5 | 124140432443022133 |
6 | 2315525553022111 |
7 | 152540604114121 |
oct | 21367112076473 |
9 | 4225023361177 |
10 | 1201402314043 |
11 | 42356a316418 |
12 | 174a0b254937 |
13 | 893a3c96829 |
14 | 4221087d911 |
15 | 213b7d8b02d |
hex | 117b9287d3b |
1201402314043 has 2 divisors, whose sum is σ = 1201402314044. Its totient is φ = 1201402314042.
The previous prime is 1201402314011. The next prime is 1201402314089. The reversal of 1201402314043 is 3404132041021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1201402314043 - 25 = 1201402314011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201402313999 and 1201402314017.
It is not a weakly prime, because it can be changed into another prime (1201402314643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600701157021 + 600701157022.
It is an arithmetic number, because the mean of its divisors is an integer number (600701157022).
Almost surely, 21201402314043 is an apocalyptic number.
1201402314043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201402314043 is an equidigital number, since it uses as much as digits as its factorization.
1201402314043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 1201402314043 its reverse (3404132041021), we get a palindrome (4605534355064).
The spelling of 1201402314043 in words is "one trillion, two hundred one billion, four hundred two million, three hundred fourteen thousand, forty-three".
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