Base | Representation |
---|---|
bin | 1010111011010011110101… |
… | …1000011100100001111011 |
3 | 1120112112101000221000111122 |
4 | 2232310331120130201323 |
5 | 3033314240124023103 |
6 | 41315102510015455 |
7 | 2346662304331004 |
oct | 256647530344173 |
9 | 46475330830448 |
10 | 12014053345403 |
11 | 39121499a924a |
12 | 14204a21a758b |
13 | 691bc7088795 |
14 | 2d76aa1c01ab |
15 | 15c7a6a8eb38 |
hex | aed3d61c87b |
12014053345403 has 2 divisors, whose sum is σ = 12014053345404. Its totient is φ = 12014053345402.
The previous prime is 12014053345387. The next prime is 12014053345433. The reversal of 12014053345403 is 30454335041021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12014053345403 - 24 = 12014053345387 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014053345433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007026672701 + 6007026672702.
It is an arithmetic number, because the mean of its divisors is an integer number (6007026672702).
Almost surely, 212014053345403 is an apocalyptic number.
12014053345403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014053345403 is an equidigital number, since it uses as much as digits as its factorization.
12014053345403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 12014053345403 its reverse (30454335041021), we get a palindrome (42468388386424).
The spelling of 12014053345403 in words is "twelve trillion, fourteen billion, fifty-three million, three hundred forty-five thousand, four hundred three".
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