12014053345433 has 2 divisors, whose sum is σ = 12014053345434. Its totient is φ = 12014053345432.

The previous prime is 12014053345403. The next prime is 12014053345439. The reversal of 12014053345433 is 33454335041021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7413487363984 + 4600565981449 = 2722772^2 + 2144893^2 .

It is an emirp because it is prime and its reverse (33454335041021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12014053345433 - 2¹⁰ = 12014053344409 is a prime.

It is not a weakly prime, because it can be changed into another prime (12014053345439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007026672716 + 6007026672717.

It is an arithmetic number, because the mean of its divisors is an integer number (6007026672717).

Almost surely, 2^{12014053345433} is an apocalyptic number.

It is an amenable number.

12014053345433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014053345433 is an equidigital number, since it uses as much as digits as its factorization.

12014053345433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 12014053345433 its reverse (33454335041021), we get a palindrome (45468388386454).

The spelling of 12014053345433 in words is "twelve trillion, fourteen billion, fifty-three million, three hundred forty-five thousand, four hundred thirty-three".