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1201408108253 is a prime number
BaseRepresentation
bin10001011110111001100…
…000001110011011011101
311020212001012022102100222
4101132321200032123131
5124140440433431003
62315530321131125
7152541004265633
oct21367140163335
94225035272328
101201408108253
11423572613721
12174a11189aa5
13893a5244c62
144221154b353
15213b8632c38
hex117b980e6dd

1201408108253 has 2 divisors, whose sum is σ = 1201408108254. Its totient is φ = 1201408108252.

The previous prime is 1201408108211. The next prime is 1201408108309. The reversal of 1201408108253 is 3528018041021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1001686710649 + 199721397604 = 1000843^2 + 446902^2 .

It is an emirp because it is prime and its reverse (3528018041021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201408108253 - 232 = 1197113140957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201408101253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600704054126 + 600704054127.

It is an arithmetic number, because the mean of its divisors is an integer number (600704054127).

Almost surely, 21201408108253 is an apocalyptic number.

It is an amenable number.

1201408108253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201408108253 is an equidigital number, since it uses as much as digits as its factorization.

1201408108253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 35.

The spelling of 1201408108253 in words is "one trillion, two hundred one billion, four hundred eight million, one hundred eight thousand, two hundred fifty-three".