Base | Representation |
---|---|
bin | 1010111011010100000001… |
… | …0111011001001101001011 |
3 | 1120112112111112010010021102 |
4 | 2232311000113121031023 |
5 | 3033314340432320131 |
6 | 41315111454532015 |
7 | 2346663452650355 |
oct | 256650027311513 |
9 | 46475445103242 |
10 | 12014103401291 |
11 | 3912175187a52 |
12 | 14204b6b0700b |
13 | 691c04563454 |
14 | 2d76b2ad00d5 |
15 | 15c7ab17b1cb |
hex | aed405d934b |
12014103401291 has 2 divisors, whose sum is σ = 12014103401292. Its totient is φ = 12014103401290.
The previous prime is 12014103401249. The next prime is 12014103401327. The reversal of 12014103401291 is 19210430141021.
12014103401291 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12014103401291 - 26 = 12014103401227 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014103401221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007051700645 + 6007051700646.
It is an arithmetic number, because the mean of its divisors is an integer number (6007051700646).
Almost surely, 212014103401291 is an apocalyptic number.
12014103401291 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014103401291 is an equidigital number, since it uses as much as digits as its factorization.
12014103401291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
The spelling of 12014103401291 in words is "twelve trillion, fourteen billion, one hundred three million, four hundred one thousand, two hundred ninety-one".
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