Base | Representation |
---|---|
bin | 1010111011010100000001… |
… | …0111011001001101101111 |
3 | 1120112112111112010010022202 |
4 | 2232311000113121031233 |
5 | 3033314340432320302 |
6 | 41315111454532115 |
7 | 2346663452650436 |
oct | 256650027311557 |
9 | 46475445103282 |
10 | 12014103401327 |
11 | 3912175187a85 |
12 | 14204b6b0703b |
13 | 691c04563481 |
14 | 2d76b2ad011d |
15 | 15c7ab17b202 |
hex | aed405d936f |
12014103401327 has 2 divisors, whose sum is σ = 12014103401328. Its totient is φ = 12014103401326.
The previous prime is 12014103401291. The next prime is 12014103401359. The reversal of 12014103401327 is 72310430141021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12014103401327 - 28 = 12014103401071 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12014103401327.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12014103401227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007051700663 + 6007051700664.
It is an arithmetic number, because the mean of its divisors is an integer number (6007051700664).
Almost surely, 212014103401327 is an apocalyptic number.
12014103401327 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014103401327 is an equidigital number, since it uses as much as digits as its factorization.
12014103401327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 12014103401327 its reverse (72310430141021), we get a palindrome (84324533542348).
The spelling of 12014103401327 in words is "twelve trillion, fourteen billion, one hundred three million, four hundred one thousand, three hundred twenty-seven".
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