Base | Representation |
---|---|
bin | 1010111011010100000100… |
… | …0000100110010010010101 |
3 | 1120112112112021102220010022 |
4 | 2232311001000212102111 |
5 | 3033314401213442043 |
6 | 41315112522234525 |
7 | 2346663643525514 |
oct | 256650100462225 |
9 | 46475467386108 |
10 | 12014114202773 |
11 | 39121802952a1 |
12 | 14204ba655a45 |
13 | 691c06875a67 |
14 | 2d76b430267b |
15 | 15c7ac0b1868 |
hex | aed41026495 |
12014114202773 has 2 divisors, whose sum is σ = 12014114202774. Its totient is φ = 12014114202772.
The previous prime is 12014114202763. The next prime is 12014114202803. The reversal of 12014114202773 is 37720241141021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11020228826929 + 993885375844 = 3319673^2 + 996938^2 .
It is a cyclic number.
It is not a de Polignac number, because 12014114202773 - 212 = 12014114198677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12014114202743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007057101386 + 6007057101387.
It is an arithmetic number, because the mean of its divisors is an integer number (6007057101387).
Almost surely, 212014114202773 is an apocalyptic number.
It is an amenable number.
12014114202773 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014114202773 is an equidigital number, since it uses as much as digits as its factorization.
12014114202773 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18816, while the sum is 35.
Adding to 12014114202773 its reverse (37720241141021), we get a palindrome (49734355343794).
The spelling of 12014114202773 in words is "twelve trillion, fourteen billion, one hundred fourteen million, two hundred two thousand, seven hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •