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12014114202773 is a prime number
BaseRepresentation
bin1010111011010100000100…
…0000100110010010010101
31120112112112021102220010022
42232311001000212102111
53033314401213442043
641315112522234525
72346663643525514
oct256650100462225
946475467386108
1012014114202773
1139121802952a1
1214204ba655a45
13691c06875a67
142d76b430267b
1515c7ac0b1868
hexaed41026495

12014114202773 has 2 divisors, whose sum is σ = 12014114202774. Its totient is φ = 12014114202772.

The previous prime is 12014114202763. The next prime is 12014114202803. The reversal of 12014114202773 is 37720241141021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11020228826929 + 993885375844 = 3319673^2 + 996938^2 .

It is a cyclic number.

It is not a de Polignac number, because 12014114202773 - 212 = 12014114198677 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12014114202743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007057101386 + 6007057101387.

It is an arithmetic number, because the mean of its divisors is an integer number (6007057101387).

Almost surely, 212014114202773 is an apocalyptic number.

It is an amenable number.

12014114202773 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014114202773 is an equidigital number, since it uses as much as digits as its factorization.

12014114202773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18816, while the sum is 35.

Adding to 12014114202773 its reverse (37720241141021), we get a palindrome (49734355343794).

The spelling of 12014114202773 in words is "twelve trillion, fourteen billion, one hundred fourteen million, two hundred two thousand, seven hundred seventy-three".