12014117 has 2 divisors, whose sum is σ = 12014118. Its totient is φ = 12014116.

The previous prime is 12014063. The next prime is 12014153. The reversal of 12014117 is 71141021.

12014117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12013156 + 961 = 3466^2 + 31^2 .

It is a cyclic number.

It is not a de Polignac number, because 12014117 - 2¹² = 12010021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12014095 and 12014104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12014017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007058 + 6007059.

It is an arithmetic number, because the mean of its divisors is an integer number (6007059).

Almost surely, 2^12014117 is an apocalyptic number.

It is an amenable number.

12014117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014117 is an equidigital number, since it uses as much as digits as its factorization.

12014117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 17.

The square root of 12014117 is about 3466.1386296569. The cubic root of 12014117 is about 229.0325907227.

Adding to 12014117 its reverse (71141021), we get a palindrome (83155138).

The spelling of 12014117 in words is "twelve million, fourteen thousand, one hundred seventeen".